本帖最后由 火凤凰 于 2014-7-4 05:37 编辑

Seebelow copy of a test conducted by Dr. Roger Hastings utilizing the 15-C2 unit.

看下面Dr. Roger Hastings复制的15-C2装置的测试。

TOWHOM IT MAY CONCERN :

给任何相当的人

OnJune 16 and 17, 1984 I ran a series of tests on Joseph Newman 's 145 lb . motorwith 14 lb . rotary . These tests show that power is generated by the motorwhich greatly exceeds the battery input power . The results are summarizedbriefly below :

1884年六月16和17号，我做了一系列关于纽曼的有14磅转子145磅发电机的测试。这些测试说明发电机产生的能量多于电池的输入能量。结果总结如下：
A . Oscilloscope Readings

Theoscilloscope showed large (1 Amp ) staircase current spikes of significant timeduration , which were initiated when the commutator switched , and flowed bothin the coil and battery portions of the circuit . A picture of this spike takenon the coil side of the commutator is attached . A block diagram of the circuitis shown below .

示波器显示了明显的有持续时间的的（大于1安）梯形电流峰，当换向器切换时开始。流向电路中的线圈和电池。一张有尖峰的图，在换向器切换在线圈一侧时拍摄，附在下面。电路的图在下面展示。


注：这个示波器的图形，我调BEDINI的时候，看到过一模一样的图。

B .Circuit Breaker Tests

Anammeter which has a built in circuit breaker was placed in the circuit . Whenthe meter was placed on the 100 ma scale, the breaker opened, both on thebattery and coil side of the commutator .

Thebreaker did not open when the meter was placed on the one amp scale, however,it was verified that a current input of more than 1.5 times the full scaledeflection did not open the breaker.

一个有断路开关的电流表加入到电路中。当电流表放到100 毫安的偏移时,开关打开,（换向器和电池侧都打开）.
当电流表电流超过1安时档位时断路器没有断开, 然而,证明多于满刻度1.5倍的输入电流没有打开断路开关.
注：这个断路器应该是类似保险丝一样的功能，这里说的意思应该是说一般电流达到一定值，这个保险丝会熔断的，但这里达到电流了却没有熔断。这里说的是冷电效应？

C .Temperature Rise

Afive hundred ohm risistor was placed in series with the battery . The resistorwas water-proofed and placed in a small thermos container with a precisionthermometer. A temperature rise of approximately one degree Centigrade wasobserved in a period of fifteen minutes. To raise the temperature of the 21grams of water by 1 degree in fifteen minutes requires at least an averagepower of:

一个500欧的电阻与电池串连。电阻是防水的，放到一个有精密温度计的保温容器中。在15分钟内观察到大约升高了1度。在15分钟内升高这21克水1度所需求最少的平均功率为：0.1w

Sincethe power supplied by the current flowing in the resistor is I2R,where I is the average current and R = 500Ω,  it follows that a current of at least 14 maon the average must flow in the circuit . This result was verifiedexperimentally by supplying 14 ma to the 500Ω resistorvia a battery and series resistors .If the current contained in the spikes(attached photo) is averaged over the cycle time, the result is consistent withan average current of 14 ma.

因为能量由电流流过电阻产生，符合I2R，I是平均电流，R = 500Ω，也就是说电路必需流过最少14毫安的电流。这个结果被实验证明，通过一个电池提供14毫安的电流流过500Ω的电阻。如果电流，包含峰值（附图中），是在周期内平均，结果是和14毫安的平均电流等同。
注：C是用电路加热水的方式来计算系统的输出能量。
2.证明大电流峰不是由电池产生。
A.    Current Readings

Whena Simpson amp meter is placed in series with the batteries, a d.c . inputcurrent of 1.2 ma is registered. The battery input current is therefore 1.2 ma.

当一个Simpson电流计和电流串连，一个12毫安的直流输入电流被检测到。电池输入因此是1.2毫安。
B.    Expected Input Current

Whenthe rotor is stopped, the input current from the batteries is measured to be 6ma (this is in agreement with 304 volts and 50 K/L coil resistance).       The coil inductance , as calculated fromthe number of wire turns and the geometry, is 16,000 Henries. At the operatingspeed of 136 r.p.m., the inductive reactance of the coil is 230 K/L., which ismuch large than the coil resistance . The expected battery input current is 304V/230 K/L= 1.3 ma, in good agreement with the measured input of 1.2 ma.

B. 期望的输入电流
当轮子停止，来自电池的输入电流为6毫安（这符合304伏和50 K/L的线圈电阻）。线圈电感，从线圈圈数和形状计算出来，是16,000 H。在136圈每分钟的速度，线圈的感抗是230 K/L，远远大于线圈电阻。期望的电流输入是304 V/230 K/L= 1.3 ma，非常好的符合测试到的输入1.2毫安。
感抗＝2*3.14*136/60*16000＝227754欧姆 差不多230k。
C.    Constant Battery Voltage

Duringfour hours of continuous running of the motor, the voltage remained constant at304 volts. If the 15 ma average currentcontained in the spikes came from the batteries, they would drain downsignificantly in the four hour period. By draining14 ma from a fresh 9 volt transistor battery identical to those on the motor itwas found that the 14 ma drain causes the voltage to drop by 2% per hour. Thusif the 14 ma were originating at the battery, the battery voltage would drop by24 volts in four hours . No drop was observed .

C.恒定的电池电压
在发电机连续运行的四个小时中，电压保持在304 v的恒定水平。如果15毫安的平均电流包含来自电池的峰值，它们将在四小时内耗尽。通过从一个9v的晶体管电池释放14毫安电流，和电动机一致，发现14毫安的消耗会引起电压每小时下降2%。因些如果14毫安完全由电池产生，电池电压将将在四小时内下降24伏。但没有发现电压下降。
注：C在证明能量不全来自于电池。
D.    Larger Current Spikes on Coil Side

Thecurrent spikes, as recorded on the scope, were larger on the coil side of thecommutator than on the battery side. Thisindicates that the spikes originate at the coil, with some loss occuring at thecommutator .

电流峰，如记录的幅度，换向器线圈一侧大于电池一侧。这指出峰值产生于线圈，在换向器处有一些的损耗。
E.    Negative Current

Asignificant portion of the spike in the battery circuit is negative (opposingthe battery voltage). The battery cannot generate such a negative current.

在电池电路峰值一个重要的部分是反向电流（和电池电压相反）。电池不能产生这样一个反向电流。
F.    Dependence Upon Rotary Position

Theintensity of the spikes varies greatly with the placement of the rotary.  For example, when the rotor is on the side(outside) of the coil the spikes are large . They virtually disappear when therotary is placed on top of the coil .

F.依赖于旋转位置
峰值的强度变化非常依赖于旋转的位置。例如，当转子在线圈一侧（外侧）峰值最大。当旋转到线圈顶部时消失。
3.功率和有用的输出

A .Output verses Input Power

Sincean average of 14 ma flows through the 50 K/L coil, the heat dissipated in thecoil is ten watts . The battery input is 1.2 ma times 304 volts, or 0.36 watts.      The heat generated in the coil is 27 timesthe input power . Note that if the ten watts were delivered by the batteries,they would drain down very quickly. These batteries have been used in frequentdemonstrations for long durations by Mr. Newman over the past several months .As mentioned above , four hours of motor operation during these tests did notmeasureably lower the battery voltage.

因为一个14毫安的平均电流流过50K/L线圈，在线圈损耗的热量是10瓦。电流输入是1.2毫安乘以304伏，或0.36瓦。线圈产生的热是输入功率的27倍。注意，如果10瓦是由电池提供，它们会很快被耗尽。在很长的时间内纽曼先生已经证明，这些电池已经被用了几个月。如上述所说，发电机运行的4个小中这些测试没有测试到低于电池的电压。
B.    Useful Output

Mr. Newman placed a 75 Watt, eight foot, flourescent tube across the motor coil,and the bulb lit to perhaps 10% of full brightness. Interestingly , when thebulb was inserted, the rotary gained speed, and the motor drew less currentfrom the batteries!       The lit 75 watttube demonstrates useful output of several watts, with a fractional watt inputpower.

纽曼先生放了一个75瓦8英尺长的荧光管穿过电机线圈，电灯泡会有亮度的10%。有趣的是，当电灯泡接入，机器会获得速度，发电机会损耗电池更少的电能！点亮75瓦的灯管证明几瓦的有用输出，只用极小瓦的输入。

Iswear the above statements are true and accurate to the best of my knowlegde.

我根据我最好的知识发誓上面的陈述是真的并精确的。


注：你可能觉得图片不够，无法想象真实的配置结构是什么样的。你可以参看英文原版，里面有一些图片，包括实物图和线路配备图，以及一些测试的波形，反正我个人觉得我已经理解了其所讲的，包括他的设备的工作结构和原理。我想你也可以理解的。